kuat arus maksimum dari rangkaian adalah

infosekilas SMA

E. 2square root of 2 A

Jawaban

R = 12 ohm ; L = 0,075 H ; C = 500 straight muF

straight omega equals 200 rad divided by straight s

Pertama-tama hitung terlebih dahulu reaktansi kapasitif dan reaktansi induktif pada rangkaian RLC.

straight X subscript straight c equals 1 over ωC equals fraction numerator 1 over denominator left parenthesis 200 right parenthesis left parenthesis 500 cross times 10 to the power of negative 6 end exponent right parenthesis end fraction equals 10 ohm

straight X subscript straight L equals ωL equals left parenthesis 200 right parenthesis left parenthesis 0 comma 075 right parenthesis equals 15 ohm

Hitung impedansi rangkaian :

straight Z equals square root of straight R to the power of blank squared end exponent plus left parenthesis straight X subscript straight L minus straight X subscript straight C right parenthesis squared end root

Z equals square root of left parenthesis 12 right parenthesis squared plus left parenthesis 15 minus 10 right parenthesis squared end root

straight Z equals square root of 144 plus 25 end root

straight Z equals square root of 169 equals 13 ohm

Besarnya kuat arus listrik maksimum yang mengalir pada rangkaian RLC adalah :

straight I subscript maks equals straight V subscript maks over straight Z

straight I equals 26 over 13 equals 2 straight A

Designed by INFO SEKITAR KITA
© Copyright 2024, All Rights Reserved